Calculate the mass of magnesium oxide that can be obtained by burning magnesium in oxygen with a volume of 4.48 liters?

Metallic magnesium reacts intensely with oxygen. The reaction is described by the following chemical reaction equation:
Mg + 1 / 2O2 = MgO;
During oxidation, one oxygen atom is attached to the magnesium atom. In this case, one molecule of magnesium oxide is synthesized.
Let’s calculate the chemical amount of oxygen.
To do this, we divide its volume by the volume of 1 mole of gas.
N O2 = 4.48 / 22.4 = 0.2 mol;
With this amount of oxygen, 2 times more magnesium will react.
Let’s calculate the weight of magnesium oxide.
To do this, we multiply the amount of the substance by the weight of 1 mole of the substance.
M MgO = 24 + 16 = 40 grams / mol; m MgO = 0.2 x 2 x 40 = 16 grams