Calculate the mass of magnesium, reacted with dilute sulfuric acid, if 33.6 hydrogen is released.

1. The equation for the reaction of magnesium with dilute sulfuric acid is:

Mg + H2SO4 = MgSO4 + H2 ↑;

2. find the chemical amount of hydrogen:

n (H2) = V (H2): Vm = 33.6: 22.4 = 1.5 mol;

3. Determine the amount and calculate the mass of magnesium:

n (Mg) = n (H2) = 1.5 mol;

m (Mg) = n (Mg) * M (Mg) = 1.5 * 24 = 1.5 * 24 = 36 g.

Answer: 36 g.