Calculate the mass of magnesium required to interact with 22.4 liters of chlorine.

1. The interaction of magnesium with chlorine occurs according to the equation:

Mg + Cl2 = MgCl2;

2. Let’s calculate the chemical amount of chlorine:

n (Cl2) = V (Cl2): Vm = 22.4: 22.4 = 1 mol;

3. Determine the amount of reacted magnesium:

n (Mg) = n (Cl2) = 1 mol;

4. Let’s calculate the mass of magnesium:

m (Mg) = n (Mg) * M (Mg) = 1 * 24 = 24 g.

Answer: 24 g.