Calculate the mass of magnesium required to react with 33.5 liters of oxygen.

Metallic magnesium reacts intensely with oxygen. The reaction is described by the following chemical reaction equation:

Mg + ½ O2 = MgO;

During oxidation, one oxygen atom is attached to the magnesium atom. In this case, one molecule of magnesium oxide is synthesized.

Let’s find the chemical amount of oxygen.

To do this, we divide its volume by the volume of 1 mole of gas.

N O2 = 33.5 / 22.4 = 1.495 mol;

With this amount of oxygen, 2 times more magnesium will react.

Let’s find its weight.

Let’s multiply the molar amount of the substance and the weight of 1 mole of the substance.

M Mg = 24 grams / mol; m Mg = 1.495 x 2 x 24 = 71.76 grams;