Calculate the mass of magnesium that can be burned in 33.6L oxygen. Chemical reaction level: 2Mg + O2 = 2MgO

To solve, we write down the process according to the condition of the problem:
X g -? V = 33.6 l;
1. 2Mg + O2 = 2MgO – compounds, magnesium oxide was formed;
2. Let’s define the values:
M (Mg) = 24.3 g / mol.
M (O2) = 32 g / mol.
3. Proportions:
1 mole of gas at normal level – 22.4 liters;
X mol (O2) – 33.6 from here, X mol (O2) = 1 * 33.6 / 22.4 = 1.5 mol.
X mol (Mg) – 1.5 mol (O2);
-2 mol – 1 mol from here, X mol (Mg) = 2 * 1.5 / 1 = 3 mol.
4. Find the mass of the metal Mg:
m (Mg) = Y * M = 3 * 24.3 = 72.9 g.
Answer: you need magnesium weighing 72.9 g.