Calculate the mass of magnesium that can be burned in oxygen with a volume of 3.6 liters.

Given:
V (O2) = 3.6 L
To find: m (Mg)
Decision:
2Mg + O2 = 2MgO
n (O2) = V / Vm = 3.6 L / 22.4 L / mol = 0.16 mol
n (O2): n (Mg) = 1: 2
n (Mg) = 0.16 mol * 2 = 0.32 mol
m (Mg) = n * M = 0.32 mol * 24 g / mol = 7.68 g
Answer: 7.68 g



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