Calculate the mass of magnesium that can fully react with 300 g of 18.25% HCL solution.

univerkov | January 17, 2021 | education

Given:
m p (HCl) = 300 g
w (HCl) = 18.25% = 0.1825
To find:
m (Mg)
Decision:
Mg + 2HCl = MgCl2 + H2
m in (HCl) = w * m p = 0.1825 * 300 g = 54.75 g
n (HCl) = m / M = 54.75 g / 36.5 g / mol = 1.5 mol
n (HCl): n (Mg) = 2: 1
n (Mg) = 1.5 mol / 2 = 0.75 mol
m (Mg) = n * M = 0.75 mol * 24 g / mol = 18 g
Answer: 18 g

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