Calculate the mass of mercury obtained from decomposition of 217 grams of mercury oxide.

1.Let’s find the amount of mercury oxide substance.

n = m: M.

M (HgO) = 201 + 16 = 217 g / mol.

n = 217 g: 217 g / mol = 1 mol.

2. Let’s compose the reaction equation for the decomposition of mercury oxide. Let us determine the quantitative ratio of mercury oxide and mercury. From two moles of mercury oxide, 2 moles of mercury are formed, that is, they are in quantitative ratios of 1: 1. The amount of substance will be the same

2HgO = 2Hg + O2.

n (HgO) = n (Hg) = 1 mol.

3. The mass of a substance is found by the formula:

m = n × M, where M is molar mass.

M (Hg) = 201 g / mol.

m = 301 g / mol × 1 mol = 301 g.

Answer: 301 g.