Calculate the mass of metal that can be obtained from 80 grams of iron oxide (3).

Given:
m (Fe2O3) = 80 g

Find:
m (Fe) -?

1) Write the reaction equation:
Fe2O3 + 3CO => 2Fe + 3CO2;
2) Calculate the molar mass of Fe2O3:
M (Fe2O3) = Mr (Fe2O3) = Ar (Fe) * N (Fe) + Ar (O) * N (O) = 56 * 2 + 16 * 3 = 160 g / mol;
3) Calculate the amount of the substance Fe2O3:
n (Fe2O3) = m (Fe2O3) / M (Fe2O3) = 80/160 = 0.5 mol;
4) Determine the amount of Fe substance:
n (Fe) = n (Fe2O3) * 2 = 0.5 * 2 = 1 mol;
5) Determine the molar mass of Fe:
M (Fe) = Ar (Fe) = 56 g / mol;
6) Calculate the mass of Fe:
m (Fe) = n (Fe) * M (Fe) = 1 * 56 = 56 g.

Answer: The mass of Fe is 56 g.



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