Calculate the mass of metallic silver obtained by oxidizing 600 g of a 40% formalin

| June 25, 2021 | education

Calculate the mass of metallic silver obtained by oxidizing 600 g of a 40% formalin solution with an excess of an ammoniacal solution of silver oxide.

The formalin mass is equal to 600 g.

The mass fraction of formalin is 40%.

Let’s determine the mass of metallic silver. First, we write down the reaction equations for this problem.

HCHO + Ag2O => HCOOH + 2Ag.

Let’s determine the mass of formalin. We use the following formula.

W = m r.v / m r-ra * 100%.

m (formalin) = 600 * 0.4 = 240 g.

Next, we determine the molar mass of formalin and silver.

M (НСОН) = 2 + 12 + 16 = 30 g / mol.

M (Ag) = 107.8 g / mol.

Next, using the reaction equation, we determine the mass of silver.

240 g formalin – x g silver.

30 g / mol – 2 * 107.8 g / mol.

X = 1725

Answer: the mass of silver is 1725 g.



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