Calculate the mass of Na which, when interacting with chloride acid, displaces 0.5 liters of hydrogen.

Let’s find the amount of hydrogen substance by the formula:

n = V: Vn.

n = 0.5 L: 22.4 L / mol = 0.022 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

2Na + 2HCl = 2NaCl + H2.

According to the reaction equation, there is 2 mol of sodium for 1 mole of hydrogen. Substances are in quantitative ratios of 2: 1.

The amount of sodium will be 2 times more than the amount of hydrogen.

n (Na) = 2n (H2) = 0.022 × 2 = 0.044 mol.

Let’s find the mass of sodium.

m = n × M.

M (Na) = 23 g / mol.

m = 23 g / mol × 0.044 mol = 1.012 g.

Answer: 1.012 g.