Calculate the mass of NaOH and the mass of water required to prepare 200 ml of a 10% NaOH solution with a density of 1.1 g / mol.

The solution consists of two components. Dissolved substance and solvent.

The weight of the solution is 200 x 1.1 = 220 grams.

Let’s calculate the weight of the alkali.

To do this, we multiply the weight of the solution by the mass fraction of alkali.

M substance = 220 x 0.1 = 22 grams;

We calculate the weight of the solvent in a similar way.

M solvent = 220 x 0.9 = 198 grams;

Check: M vitriol + M solvent = M solution = 22 + 198 = 220 grams;