Calculate the mass of nitric acid that can be obtained from 17 g of sodium nitrate by the action with

Calculate the mass of nitric acid that can be obtained from 17 g of sodium nitrate by the action with concentrated sulfuric acid, if the mass fraction of the acid yield is 0.96.

Given:
m (NaNO3) = 17 g
η (HNO3) = 0.96

To find:
m pract. (HNO3) -?

1) NaNO3 + H2SO4 => HNO3 + NaHSO4;
2) M (NaNO3) = Mr (NaNO3) = Ar (Na) * N (Na) + Ar (N) * N (N) + Ar (O) * N (O) = 23 * 1 + 14 * 1 + 16 * 3 = 85 g / mol;
3) n (NaNO3) = m / M = 17/85 = 0.2 mol;
4) n theory. (HNO3) = n (NaNO3) = 0.2 mol;
5) n practical (HNO3) = η * n theory. = 0.96 * 0.2 = 0.192 mol;
6) M (HNO3) = Mr (HNO3) = Ar (H) * N (H) + Ar (N) * N (N) + Ar (O) * N (O) = 1 * 1 + 14 * 1 + 16 * 3 = 63 g / mol;
7) m practical. (HNO3) = n practical. * M = 0.192 * 63 = 12.01 g.

Answer: The practical mass of HNO3 is 12.01 g.