Calculate the mass of nitrobenzene obtained from 300 liters of benzene, 25℅ impurities.

Let’s implement the solution:
1. By the condition of the problem, we write down the equation:
V = 300 l; 25% impurities. X g -?
С6Н6 + HNO3 = C6H5NO2 + H2O – substitutions, nitrobenzene was obtained;
2. Calculations:
M (C6H6) = 78 g / mol;
M (C6H5NO2) = 123 g / mol.
3. Determine the amount of the original substance, the mass without impurities:
1 mole of gas at normal level – 22.4 liters;
X mol (C6H6) – 300 liters from here, X mol (C6H6) = 1 * 300 / 22.4 = 13.39 mol;
m (C6H6) = Y * M = 13.39 * 78 = 1044.42 g;
1044.42 (1 – 0.25) = 783.3 g (without impurities);
Y (C6H6) = m / M = 783.3 / 78 = 10 mol;
Y (C6H5NO2) = 10 mol since the amount of these substances according to the equation is 1 mol.
4. Find the mass of the product:
m (C6H5NO2) = Y * M = 10 * 123 = 1230 g.
Answer: nitrobenzene weighing 1230 g was obtained.