Calculate the mass of nitrobenzene, which was obtained by the interaction of 780g.

Calculate the mass of nitrobenzene, which was obtained by the interaction of 780g. benzene containing 40% impurity with nitric acid?

Let’s compose the equation of the benzene nitration process:

C6H6 + HNO3 = C6H5NO2 + H2O – substitution, nitrobenzene is formed;

Let’s make the calculations:
M (C6H6) = 78 g / mol;

M (C6H5NO2) = 123 g / mol;

m (C6H6) = 780 (1 – 0.40) = 468 g (mass without impurity).

3. Determine the amount of the original substance:

Y (C6H6) = m / M = 468/78 = 6 mol;

Y (C6H5NO2) = 6 mol since the amount of substances is 1 mol.

4. Find the mass of the product:

m (C6H5NO2) = Y * M = 6 * 123 = 738 g

Answer: obtained nitrobenzene weighing 738 g