Calculate the mass of oxygen required to burn 44.8 liters of acetylene.

The oxidation reaction of acetylene with oxygen is described by the following chemical reaction equation:

2C2H2 + 5O2 = 4CO2 + 2H2O;

2 moles of acetylene are reacted with 5 moles of oxygen.

Let’s calculate the available chemical amount of acetylene substance.

To do this, we divide the volume of gas by the volume of 1 mole of ideal gas. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N C2H2 = 44.8 / 22.4 = 2 mol;

To burn such an amount of matter, you need to take 2 x 5/2 = 5 mol of oxygen.

Let’s calculate its weight.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 5 x 32 = 160 grams;