Calculate the mass of oxygen that can be obtained from the decomposition of potassium permanganate weighing 100 g?

univerkov | January 17, 2021 | education

Given:
m (KMnO4) = 100 g
To find:
m (O2)
Decision:
2KMnO4 = K2MnO4 + MnO2 + O2
n (KMnO4) = m / M = 100 g / 158 g / mol = 0.63 mol
n (KMnO4): n (O2) = 2: 1
n (O2) = 0.63 mol / 2 = 0.315 mol
m (O2) = n * M = 0.315 mol * 32 g / mol = 10.08 g
Answer: 10.08 g

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