Calculate the mass of oxygen that reacts with 274 grams of barium (2).
September 19, 2021 | education
| 1. We write down the reaction of interaction of barium with oxygen:
2Ba + O2 = 2BaO;
2. find the chemical amount of barium:
n (Ba) = m (Ba): M (Ba) = 274: 137 = 2 mol;
3. find the amount of oxygen and calculate its mass:
n (O2) = n (Ba): 2 = 2: 2 = 1 mol;
m (O2) = n (O2) * M (O2) = 1 * 32 = 32 g.
Answer: 32 g.
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