Calculate the mass of phosphoric acid that can be obtained from 33 g

Calculate the mass of phosphoric acid that can be obtained from 33 g of calcium orthophosphate and compared to a theoretical possible yield of 80%.

To solve, we will compose the equation of the process:

Ca3 (PO4) 2 + 3H2SO4 = 3CaSO4 + 2H3PO4 – ion exchange, orthophosphoric acid is formed;
Calculations by formulas:
M Ca3 (PO4) 2 = 309.8 g / mol;

M (H3PO4) = 97.9 g / mol;

Y Ca3 (PO4) 2 = m / M = 33 / 309.8 = 0.1 mol.

Proportion:
0.1 mol Ca3 (PO4) 2 – X mol (H3PO4);

-1 mol -2 mol hence, X mol (H3PO4) = 0.1 * 2/1 = 0.2 mol.

Find the mass of the product:
m (H3PO4) = Y * M = 0.2 * 97.9 = 19.58 g (theoretical weight);

m (H3PO4) = 0.80 * 19.58 = 15.7 g (practical weight).

Answer: received orthophosphoric acid weighing 15.7 g