Calculate the mass of phosphoric acid which is formed by the interaction of phosphorus oxide (5) with

Calculate the mass of phosphoric acid which is formed by the interaction of phosphorus oxide (5) with a chemical amount of 0.25 mol with water.

Given:
V (nu) (P2O5) = 0.25 mol
To find:
m (H3PO4) -?
Decision:
V = 0.25 V-?
m-?
H2O + 3P2O5 = 2H3PO4
3 mol. 2 mol.
We emphasize working substances.
1) According to the condition, 3 mol P2O5 — 2 mol H3PO4
According to the equation 0.25 mol P2O5 — x mol H3PO4
x = (0.25 * 2) /3=0.16mol
2) m (H3PO4) = M (H3PO4) * V (H3PO4)
M (H3PO4) = 1 * 3 + 31 + 16 * 4 = 82 g / mol
m (H3PO4) = 82 * 0.16 = 13.12 gr.
Answer: m (H3PO4) = 13.12 gr.