Calculate the mass of phosphorus and the mass of oxygen that will be required to obtain phosphorus (v)

Calculate the mass of phosphorus and the mass of oxygen that will be required to obtain phosphorus (v) oxide with a mass of 71g

The oxidation reaction of phosphorus to oxygen is described by the following chemical reaction equation.

4P + 5O2 = 2P2O5;

The phosphorus oxide molecule has two phosphorus atoms. Therefore, to obtain one mole of phosphorus oxide, two moles of phosphorus are required.

Let’s find the amount of the substance contained in 71 grams of phosphorus oxide.

Its molar mass is.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

The amount of the substance will be.

N P2O5 = 71/142 = 0.5 mol;

Let’s find the mass and amount of the phosphorus substance.

N P = N P2 O5 x 2 = 0.5 x 2 = 1 mol;

M P = 31 grams / mol;

m P = 31 x 1 = 31 grams;

N O2 = N P x5 / 4 = 1 x 5/4 = 1.25 mol;

Its molar mass is.

M O2 = 16 x 2 = 32 grams / mol;

The mass of the substance will be.

m O2 = 32 x 1.25 = 40 grams;