Calculate the mass of phosphorus and the mass of oxygen that will be required to obtain

Calculate the mass of phosphorus and the mass of oxygen that will be required to obtain phosphorus (V) oxide weighing 71 g.

The synthesis reaction of pentavalent phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 phosphorus atoms interact with 5 oxygen molecules. During the reaction, 2 molecules of pentavalent phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance contained in phosphorus oxide weighing 71 grams.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

N P2O5 = 71/142 = 0.5 mol;

To synthesize such an amount of oxide, it is necessary to take 0.5 x 2 = 1 mol of phosphorus and 0.5 / 2 x 5 = 1.25 mol of oxygen.

Let’s calculate the weights of these substances:

M P = 31 grams / mol;

m P = 1 x 31 = 31 grams;

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 1.25 x 32 = 40 grams;