Calculate the mass of phosphorus oxide (Y), which will result from combustion of 93g. phosphorus.

Calculate the mass of phosphorus oxide (Y), which will result from combustion of 93g. phosphorus. Calculate the mass of oxygen that will be required for this reaction.

The oxidation reaction of phosphorus to oxygen is described by the following chemical reaction equation.

4P + 5O2 = 2P2O5;

The phosphorus oxide molecule has two phosphorus atoms. Therefore, to obtain one mole of phosphorus oxide, two moles of phosphorus are required.

Let’s find the amount of the substance contained in 93 grams of phosphorus.

M P = 31 grams / mol;

N P = 93/31 = 3 mol;

Let us find the mass and amount of the phosphorus oxide substance.

N P2 O5 = N P / 2 = 3/2 = 1.5 mol;

Its molar mass is.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

The mass of the substance will be.

m P2O5 = 142 x 3 = 426 grams;

Let’s find the mass and amount of oxygen.

N O2 = N P x5 / 4 = 3 x 5/4 = 3.75 mol;

Its molar mass is.

M O2 = 16 x 2 = 32 grams / mol;

The mass of the substance will be.

m O2 = 32 x 3.75 = 120 grams;