Calculate the mass of phosphorus required to obtain phosphorus oxide 5 weighing 33.5 grams.

The oxidation reaction of phosphorus to oxygen is described by the following chemical reaction equation.

4P + 5O2 = 2P2O5;

The phosphorus oxide molecule has two phosphorus atoms. Therefore, to obtain one mole of phosphorus oxide, two moles of phosphorus are required.

Let’s find the amount of the substance contained in 33.5 grams of phosphorus oxide.

Its molar mass is.

M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;

The amount of the substance will be.

N P2O5 = 33.5 / 142 = 0.2359 mol;

Let’s find the mass and amount of the phosphorus substance.

The amount of the substance will be.

N P = N P2 O5 x 2 = 0.2359 x 2 = 0.4718 mol;

M P = 31 grams / mol;

The mass of the substance will be:

m P = 31 x 0.4718 = 14.6258 grams;