Calculate the mass of phosphorus required to react with 56 liters of oxygen.

The synthesis reaction of phosphorus oxide is described by the following chemical reaction equation:

4P + 5O2 = 2P2O5;

4 moles of phosphorus react with 5 moles of oxygen. In this reaction, 2 moles of phosphorus oxide are synthesized.

Let’s calculate the chemical amount of a substance in oxygen with a mass of 16 grams.

To do this, divide the volume of oxygen by the volume of 1 mole of gas.

N O2 = 56 / 22.4 = 2.5 mol;

With this amount of oxygen, 2.5 / 5 x 4 = 2 mol of phosphorus will react.

Let’s calculate its weight.

M P = 31 grams / mol;

m P = 2 x 31 = 62 grams;