Calculate the mass of potassium alcoholate, which is formed by the interaction of 5.85 g

Calculate the mass of potassium alcoholate, which is formed by the interaction of 5.85 g of potassium with propanol weighing 7.2 g

To solve it, you need to make an equation:
1. 2С3Н7ОН + 2K = H2 + 2C3H7OK – substitution reaction, obtained potassium alcoholate, hydrogen gas;
2. We calculate the molar masses of substances:
M (C3H7OH) = 60 g / mol;
M (K) = 39.1 g / mol;
M (C3H7OK) = 98.1 g / mol.
3. Determine the number of moles of starting materials: propanol, potassium.
V (C3H7OH) = m / M = 7.2 / 60 = 0.12 mol (deficient substance);
Y (K) = m / M = 5.85 / 39.1 = 0.15 mol.
4. Let’s make the proportion according to the equation:
0.12 mol (C3H7OH) – X mol (C3H7OK);
-2 mol – 2 mol from here, X mol (C3H7OK) = 0.12 mol.
5. Find the mass of organic matter – potassium alcoholate:
m (C3H7OK) = Y * M = 0.12 * 98.1 = 11.77 g.
Answer: an alcoholate weighing 11.77 g was obtained.