Calculate the mass of potassium chloride that is formed by the interaction of 69 g of potassium

Calculate the mass of potassium chloride that is formed by the interaction of 69 g of potassium carbonate with hydrochloric acid.

The reaction of dissolving sodium potassium in hydrochloric acid is described by the following chemical reaction equation:

K2CO3 + 2HCl = 2KCl + CO2 + H2O;

When 1 mol of potassium carbonate is dissolved in acid, 1 mol of gaseous carbon dioxide is synthesized. This consumes 2 mol of hydrochloric acid.

Let’s calculate the chemical amount of a substance containing 69 grams of potassium carbonate.

М К2СО3 = 39 x 2 + 12 + 16 x 3 = 138 grams / mol;

N K2CO3 = 69/138 = 0.5 mol;

Let’s calculate the chemical amount of a substance containing 100 grams of nitric acid.

M HNO3 = 1 + 14 + 16 x 3 = 63 grams / mol;

N HNO3 = 100/63 = 1.587 mol;

Thus, when 0.5 mol of soda is dissolved, 0.5 mol of carbon dioxide is synthesized. This will require 0.5 x 2 = 1.0 mol of acid.

Let’s calculate the volume of carbon dioxide. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.5 x 22.4 = 11.2 liters;