Calculate the mass of potassium hydroxide and the volume of hydrogen, which are formed

Calculate the mass of potassium hydroxide and the volume of hydrogen, which are formed by the interaction of 7.8 g of potassium with water.

The reaction of potassium with water is described by the following chemical reaction equation.

K + H2O = KOH + ½ H2;

For one mole of potassium, one mole of alkali and half a mole of hydrogen are formed.

Let’s find the amount of the substance in 7.8 grams of potassium.

M K = 39 grams / mol;

N K = 7.8 / 39 = 0.2 mol;

Determine the mass of 0.2 mol KOH.

M KOH = 39 + 16 + 1 = 56 grams / mol;

m KOH = 56 x 0.2 = 11.2 grams;

Let us determine the volume of 0.1 mol of hydrogen.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

0.1 mol of hydrogen will take up a volume equal to 2.24 liters.