Calculate the mass of potassium hydroxide reacted with sulfuric acid if 104 g of salt is formed as a result.
| June 16, 2021 | education
Reaction of potassium hydroxide with sulfuric acid.
2KOH + H2SO4 = K2SO4 + 2H2O.
The number of moles of the formed salt.
n (K2SO4) = m / Mr = 104 g / 174 g / mol = 0.6 mol. The number of mol of potassium hydroxide will be twice as large as n (KOH) = 2 • 0.6 mol = 1.2 mol.
The mass of potassium hydroxide reacted.
m (KOH) = n • Mr = 1.2 mol • 56 g / mol = 67.2 g.
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