Calculate the mass of potassium hydroxide required to neutralize 6.3 grams of nitric acid.

For the solution, we write:

Xr -? m = 6.3 g

KOH + HNO3 = KNO3 + H2O – ion exchange, obtained potassium nitrate, water;

Calculations:
M (KOH) = 39.1 + 17 = 56.1 g / mol;

M (HNO3) = 63 g / mol.

Determine the amount of the original substance:
Y (HNO3) = m / M = 6.3 / 63 = 0.1 mol.

Y (KOH) = 0.1 mol since the amount of substances is equal to 1 mol.

Find the mass of the base:
m (KOH) = Y * M = 01 * 56.1 = 5.61 g

Answer: the mass of potassium hydroxide is 5.61 g