Calculate the mass of potassium hydroxide required to neutralize 98 g of a sulfuric acid solution

Calculate the mass of potassium hydroxide required to neutralize 98 g of a sulfuric acid solution with a mass fraction of acid of 30%

Given:
m solution (H2SO4) = 98 g
ω (H2SO4) = 30%

To find:
m (KOH) -?

Decision:
1) 2KOH + H2SO4 => H2SO4 + 2H2O;
2) m (H2SO4) = ω * m solution / 100% = 30% * 98/100% = 29.4 g;
3) n (H2SO4) = m / M = 29.4 / 98 = 0.3 mol;
4) n (KOH) = n (H2SO4) * 2 = 0.3 * 2 = 0.6 mol;
5) m (KOH) = n * M = 0.6 * 56 = 33.6 g.

Answer: The mass of KOH is 33.6 g.