Calculate the mass of potassium hydroxide that can be obtained by the action of water on potassium oxide weighing 28.2 g.

Calculate the mass of potassium hydroxide that can be obtained by the action of water on potassium oxide weighing 28.2 g. How much of the water substance will be consumed in this case?

Given:
m (K2O) = 28.2 g
To find:
m (KOH)
Decision:
H2O + K2O = 2KOH
n (K2O) = m / M = 28.2 g / 94 g / mol = 0.3 mol
n (K2O): n (KOH) = 1: 2
n (KOH) = 0.3 mol * 2 = 0.6 mol
m (KOH) = n * M = 0.6 mol * 56 g / mol = 33.6 g
Answer: 33.6 g