Calculate the mass of potassium hydroxide that was spent on neutralizing

| September 26, 2021 | education

Calculate the mass of potassium hydroxide that was spent on neutralizing ethanic acid with an amount of 4 mol. How much salt is formed?

Let’s implement the solution, compose an equation according to the condition of the problem:
CH3COOH + KOH = CH3COOK + H2O – exchange reaction, an organic potassium acetate salt was obtained;
According to the reaction equation, the amount of moles of acetic acid, potassium hydroxide and sodium acetate are equal to 1 mol, which means that Y (KOH) = 4 mol, Y (CH3COOK) = 4 mol.
Let’s calculate the molar masses of substances:
M (KOH) = 56.1 g / mol;
M (CH3COOK) = 98.1 g / mol.
We find the mass of potassium hydroxide and potassium acetate by the formula:
m (KOH) = Y * M = 4 * 56.1 = 224.4 g;
m (CH3COOK) = Y * M = 4 * 98.1 = 392.4 g.
Answer: the mass of potassium hydroxide is 224.4 g, the mass of potassium acetate is 392.4 g.



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