1. We write down the equation of interaction of potassium with bromine:
2K + Br2 = 2KBr;
2.Calculate the chemical amount of bromine:
n (Br2) = m (Br) 2: M (Br2) = 16: 160 = 0.1 = mol;
3.According to the equation, potassium reacts twice as much, we find its amount:
n (K) = n (Br2) * 2 = 0.1 * 2 = 0.2 mol;
4.calculate the mass of potassium:
m (K) = n (K) * M (K) = 0.2 * 39 = 7.8 g.
Answer: 7.8 g.
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