Calculate the mass of products that are formed when burning hexane with a mass of 90 g?

The hexane oxidation reaction is described by the following chemical reaction equation.
2C6H14 + 19O2 = 12CO2 + 14H2O;
According to the coefficients of this equation, 19 oxygen molecules are required to oxidize 2 hexane molecules. This synthesizes 12 molecules of carbon dioxide and 14 molecules of water.
Let’s calculate the amount of hexane reacted.
To do this, divide its weight by the weight of 1 mole of hexane.
M C6H14 = 12 x 6 + 14 = 86 grams / mol;
N C6H14 = 90/86 = 1.047 mol;
The amount and weight of synthesized water will be:
N H2O = 1.047 x 14/2 = 7.329 mol;
M H2O = 2 + 16 = 18 grams / mol;
m H2O = 7.329 x 18 = 131.92 mol;
The amount and weight of synthesized carbon dioxide will be:
N CO2 = 1.047 x 12/2 = 6.282 mol;
M CO2 = 12 + 16 x 2 = 44 grams / mol;
m CO2 = 6.282 x 44 = 276.41 mol;