Calculate the mass of quicklime obtained by firing 200 kg of limestone with impurities of 25%.

The decomposition reaction of limestone is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

When 1 mol of limestone is decomposed, 1 mol of gaseous carbon dioxide is synthesized.

This also synthesizes 1 mol of calcium oxide

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 200,000 x 0.75 / 100 = 1,500 mol;

During the reaction, the same amount of calcium oxide will be synthesized.

N CaO = 1,500 mol;

Its weight will be:

M CaO = 40 + 16 = 56 grams / mol;

m CaO = 56 x 1,500 = 84,000 grams = 84 kg;