The decomposition reaction of limestone is described by the following chemical reaction equation:
CaCO3 = CaO + CO2;
When 1 mol of limestone is decomposed, 1 mol of gaseous carbon dioxide is synthesized.
This also synthesizes 1 mol of calcium oxide
Let’s calculate the available chemical amount of calcium carbonate substance.
M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;
N CaCO3 = 200,000 x 0.75 / 100 = 1,500 mol;
During the reaction, the same amount of calcium oxide will be synthesized.
N CaO = 1,500 mol;
Its weight will be:
M CaO = 40 + 16 = 56 grams / mol;
m CaO = 56 x 1,500 = 84,000 grams = 84 kg;
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