Calculate the mass of salt and water required to prepare 200 g of 30% salt solution.

Given:
m solution (salt) = 200 g
ω (salt) = 30%

To find:
m (salt) -?
m (water) -?

1) m (salt) = ω * m solution / 100% = 30% * 200/100% = 60 g;
2) m (water) = m solution (salt) – m (salt) = 200 – 60 = 140 g.

Answer: The mass of salt is 60 g; water – 140 g.



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