Calculate the mass of salt formed by the interaction of 10 g of NaOH and 200 g of a 15% HBr solution.

1. Let’s write down the reaction equation:

NaOH + HBr = NaBr + H2O;

2. find the chemical amount of sodium hydroxide:

n (NaOH) = m (NaOH): M (NaOH);

M (NaOH) = 23 + 17 = 40 g / mol;

n (NaOH) = 10: 40 = 0.25 mol;

3. Determine the mass and amount of hydrogen bromide:

m (HBr) = w (HBr) * m (solution) = 0.15 * 200 = 30 g;

n (HBr) = m (HBr): M (HBr) = 30: 81 = 0.37 mol;

4. there is a lack of hydroxide, we determine the amount of sodium bromide by it:

n (NaBr) = n (NaOH) = 0.25 mol;

5.Calculate the mass of the formed salt:

m (NaBr) = n (NaBr) * M (NaBr);

M (NaBr) = 23 + 80 = 103 g / mol;

m (NaBr) = 0.25 * 103 = 25.75 g.

Answer: 25.75 g.