Calculate the mass of salt formed by the interaction of sodium sulfate weighing 30 grams with barium hydroxide.

univerkov | November 29, 2020 | education

n (Na2SO4) = m / M = 30g / 142g / mol = 0.21 mol
Na2SO4 + Ba (OH) 2 = BaSO4 + 2NaOH
UHR 1mol 1mol
For s-th 0.21 mol n-?
n (BaSO4) = n (Na2SO4) = 0.21 mol
m (BaSO4) = n * M = 0.21 mol * 233g / mol = 48.93g
Answer: m (BaSO4) = 48.93g

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