Calculate the mass of salt obtained by reacting 4.6 g of sodium with excess sulfur.

univerkov | January 17, 2021 | education

Given:
m (Na) = 4.6 g
To find:
m (Na2S)
Decision:
2Na + S = Na2S
n (Na) = m / M = 4.6 g / 23 g / mol = 0.2 mol
n (Na): n (Na2S) = 2: 1
n (Na2S) = 0.2 mol / 2 = 0.1 mol
m (Na2S) = n * M = 0.1 mol * 78 g / mol = 7.8 g
Answer: 7.8 g

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