Calculate the mass of salt obtained by the interaction of 6.72 m3 of chlorine with iron.

1. Let’s compose the equation of the chemical reaction:

2Fe + 3Cl2 = 2FeCl3.

2. Find the chemical amount of chlorine (Vm – molar volume, constant equal to 22.4 l / mol):

6.72 m3 = 6720 l.

n (Cl2) = V (Cl2) / Vm = 6720 L / 22.4 L / mol = 300 mol.

3. According to the reaction equation, we find the chemical amount of ferric chloride, and then its mass:

n (FeCl3) = n (Cl2) / 3 * 2 = 300 mol / 3 * 2 = 200 mol.

m (FeCl3) = n (FeCl3) * M (FeCl3) = 200 mol * 162.5 g / mol = 32500 g = 32.5 kg.

Answer: m (FeCl3) = 32.5 kg.