Calculate the mass of salt that can be obtained by reacting 150 g of a 5% solution of aminoacetic acid with the required

Calculate the mass of salt that can be obtained by reacting 150 g of a 5% solution of aminoacetic acid with the required amount of sodium hydroxide. How many grams of a 12% alkali solution will it take for the reaction?

Given:
m solution (NH2-CH2-COOH) = 150 g
w (NH2-CH2-COOH) = 5% = 0.05
w (NaOH) = 12% = 0.12
To find:
m (NH2-CH2-COONa), m solution (NaOH)
Decision:
NH2-CH2-COOH + NaOH = NH2-CH2-COONa + H2O
m in islands (NH2-CH2-COOH) = w * m solution = 0.05 * 150 g = 7.5 g
n (NH2-CH2-COOH) = m / M = 7.5 g / 75 g / mol = 0.1 mol
n (NH2-CH2-COOH): n (NH2-CH2-COONa) = 1: 1
n (NH2-CH2-COONa) = 0.1 mol
m (NH2-CH2-COONa) = n * M = 0.1 mol * 97 g / mol = 9.7 g
n (NH2-CH2-COONa): n (NaOH) = 1: 1
n (NaOH) = 0.1 mol
m in islands (NaOH) = n * M = 0.1 mol * 40 g / mol = 4 g
m solution (NaOH) = m in-va / w = 4 g / 0.12 = 33.3 g
Answer: m (NH2-CH2-COONa) = 9.7 g, m (NaOH) = 33.3 g



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