Calculate the mass of salt that can be obtained in the reaction of magnesium (excess) with sulfuric acid weighing 9.8 g.

univerkov | April 9, 2021 | education

1.Let’s find the amount of substance H2SO4.

M (H2SO4) = 98 g / mol.

n = 9.8 g: 98 g / mol = 0.1 mol.

Let’s find the quantitative ratios of substances.

Mg + H2SO4 = MgSO4 + H2.

For 1 mol of H2SO4, there is 1 mol of MgSO4.

Substances are in quantitative ratios 1: 1.

The amount of substance is equal.

n (H2SO4) = n (MgSO4) = 0.1 mol.

3.Let’s find the mass of MgSO4.

m = nM.

M (MgSO4) = 120 g / mol.

m = 0.1 mol × 120 g / mol = 12 g.

Answer: 12 g.

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