Calculate the mass of salt that is formed by the interaction of NaOH with a mass of 16 g and CO2 with a mass of 4.2 g.

1. To correctly write the reaction equation, we will establish the ratio of the reactants by finding the chemical amounts of sodium hydroxide and carbon dioxide:

n (NaOH) = m (NaOH): M (NaOH);

M (NaOH) = 23 + 17 = 40 g / mol;

n (NaOH) = 16: 40 = 0.4 mol;

n (CO2) = m (CO2): M (CO2);

M (CO2) = 12 + 32 = 44 g / mol;

n (CO2) = 4.2: 44 = 0.095 mol;

2.Sodium hydroxide is taken in a much greater excess, which means that the reaction proceeds according to the equation:

CO2 + 2NaOH = Na2CO3 + H2O;

3. Determine the amount of sodium carbonate formed:

n (Na2CO3) = n (CO2) = 0.095 mol;

4.calculate the mass of salt:

m (Na2CO3) = n (Na2CO3) * M (Na2CO3);

M (Na2CO3) = 23 * 2 + 12 + 3 * 16 = 106 g / mol;

m (Na2CO3) = 0.095 * 106 = 10.07 g.

Answer: 10.07 g.