Calculate the mass of salt that is formed when an excess of hydrochloric

Calculate the mass of salt that is formed when an excess of hydrochloric acid solution interacts with a solution containing 4 g of sodium hydroxide.

Given:
m in islands (NaOH) = 4 g
To find:
m (NaCl)
Decision:
NaOH + HCl = NaCl + H2O
n (NaOH) = m / M = 4 g / 40 g / mol = 0.1 mol
n (NaOH): n (NaCl) = 1: 1
n (NaCl) = 0.1 mol
m (NaCl) = n * M = 0.1 mol * 58.5 g / mol = 5.85 g
Answer: 5.85 g