Calculate the mass of sediment, cat. is formed when an excess of sodium chloride solution

Calculate the mass of sediment, cat. is formed when an excess of sodium chloride solution is added to 100 g of a 15% solution of silver nitrate.

Given:

m (AgNO3) = 100 g

w% (AgNO3) = 15%

To find:

m (draft) -?

Decision:

AgNO3 + NaCl = AgCl + NaNO3, – we solve the problem, relying on the composed reaction equation:

1) Find the mass of silver nitrate that has reacted:

m (AgNO3) = 100 g * 0.15 = 15 g

2) Find the amount of silver nitrate:

n (AgNO3) = m: M = 15 g: 170 g / mol = 0.088 mol

3) We compose a logical expression:

If 1 mol of AgNO3 gives 1 mol of AgCl,

then 0.088 mol of AgNO3 will give x mol of AgCl,

then x = 0.088 mol.

4) Find the mass of precipitated silver chloride:

m (AgCl) = n * M = 0.088 mol * 143.5 g / mol = 12.628 g.

Answer: m (AgCl) = 12.628 g.