Calculate the mass of sediment that is formed by passing 6, 72 liters of carbon dioxide through lime water, if the product yield is 80%

univerkov | December 10, 2020 | education

lime water Ca (OH) 2
Ca (OH) 2 + CO2 = CaCO3 + H2O
n (CO2) = 6.72 ^ 22.4 = 0.3 mol
hence n (CaCO3) = 0.3 mol
m theor (CaCO3) = 0.3 * (12 + 40 + 16 * 3) = 30gr
m practical = 30 * 0.8 = 24 g
answer 24 grams

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