Calculate the mass of silicic acid obtained by the interaction of potassium silicate weighing 18 g with hydrochloric acid.

1. The interaction of potassium silicate with hydrochloric acid proceeds according to the equation:

K2SiO3 + 2HCl = H2SiO3 + 2KCl;

2.Calculate the chemical amount of potassium silicate:

n (K2SiO3) = m (K2SiO3): M (K2SiO3);

M (K2SiO3) = 39 * 2 + 28 + 3 * 16 = 154 g / mol;

n (K2SiO3) = 18: 154 = 0.1169 mol;

3.determine the amount of acid obtained:

n (H2SiO3) = n (K2SiO3) = 0.1169 mol;

4.Calculate the mass of silicic acid:

m (H2SiO3) = n (H2SiO3) * M (H2SiO3);

M (H2SiO3) = 2 + 28 + 3 * 16 = 78 g / mol;

m (H2SiO3) = 0.1169 * 78 = 9.12 g.

Answer: 9.12 g.