Calculate the mass of silicic acid that can be obtained by the interaction of sodium

Calculate the mass of silicic acid that can be obtained by the interaction of sodium silicate and a solution of hydrochloric acid weighing 73 g with a mass fraction of 25%

Given:

m (HCl) = 73 g

w% (HCL) = 25%

To find:

m (H2SiO3) -?

Decision:

2HCl + Na2SiO3 = H2SiO3 + 2NaCl, – we solve the problem, relying on the composed reaction equation:

1) Find the mass of the acid in the reacted solution:

m (HCl) = 73 g * 0.25 = 18.25 g

2) Find the amount of acid:

n (HCl) = m: M = 18.25 g: 36.5 g / mol = 0.5 mol

3) We compose a logical expression:

If 2 mol HCl gives 1 mol H2SiO3,

then 0.5 mol HCl will give x mol H2SiO3,

then x = 0.25 mol.

4) Find the mass of silicic acid precipitated during the reaction:

m (H2SiO3) = n * M = 0.25 mol * 78 g / mol = 19.5 g /

Answer: m (H2SiO3) = 19.5 g.