Calculate the mass of silicic acid that can be obtained from sodium silicate weighing 50 g.

Calculate the mass of silicic acid that can be obtained from sodium silicate weighing 50 g. and a solution of hydrochloric acid weighing 73 g with a mass fraction of HCl 25%?

When sodium silicate and hydrochloric acid interact, the following chemical reaction occurs:

Na2SiO3 + 2HCl = 2NaCl + H2SiO3;

Let’s calculate the chemical amount of sodium silicate:

To do this, we divide its weight by the mass of 1 mole of the substance.

M Na2SiO3 = 23 x 2 + 28 + 16 x 3 = 122 grams / mol; n Na2SiO3 = 50/122 = 0.41 mol;

Determine the chemical amount of hydrochloric acid:

For this purpose, we divide its weight by the mass of 1 mole of the substance.

M HCl = 1 + 35.5 = 36.5 grams / mol; n HCl = 73 x 0.25 / 36.5 = 0.5 mol;

With 0.5 mol of hydrochloric acid, 0.5 / 2 = 0.25 mol of sodium silicate will react and an equivalent amount of silicic acid will be obtained. Sodium silicate is taken in excess.

Let’s find its weight.

To do this, we multiply the amount of a substance by its molar weight.

M H2SiO3 = 2 + 28 + 16 x 3 = 78 grams / mol; m H2SiO3 = 0.25 x 78 = 19.5 grams;